Simultaneity-Time Simultaneity-Time

Simultaneity-Time Simultaneity-Time

by T L Hurst

Velocity Effect continued...

diagram 5 At time t0: A is a distance s0 from the transmitter, and is travelling away from it at velocity v. B is stationary with respect to the transmitter at a distance s2. In B's rest frame, the time signal "t0" is approaching him at the velocity c, such that he will receive the time signal "t0" at time t2.

At time t1: A is a distance s1 from the transmitter when the time signal "t1" is emitted. In A's rest frame, A is stationary and the time signal is approaching him at the velocity c, such that he will receive the "t1" time signal at time t2.

At time t2: A and B are adjacent, but A receives the time signal "t1", whilst B receives time signal "t0".

So, we can say that the time taken for the t1 signal to reach A is t2 - t1. In that time, A moves s2 - s1 at velocity v (with respect to the transmitter). Therefore:

(t2 - t1) = (s2 - s1)/v

or

(s2 - s1) = v(t2 - t1)

Note:

continue...

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